2n^2-50n=0

Solution for 2n^2-50n=0 equation:

2n^2-50n=0

a = 2; b = -50; c = 0;
Δ = b2-4ac
Δ = -502-4·2·0
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-50}{2*2}=\frac{0}{4}
=0
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+50}{2*2}=\frac{100}{4}
=25
$